8th grade · Math · Unit 16 of 19
Cones, Cylinders & Spheres
Volume of round solids
What your child practices
Using the volume formulas for cylinders, cones and spheres, in terms of π and with 3.14.
New York State Learning Standards learning standard: NY-8.G.9 · using the formulas for the volumes of cones, cylinders and spheres
How we explain it
Children can open this short lesson before they practice.
- Cylinder: V = πr²h.
- Cone: V = ⅓πr²h, one third of the matching cylinder.
- Sphere: V = (4/3)πr³.
Example: A cylinder has radius 3 cm and height 5 cm. What is its volume, in terms of π? r² = 9. 9 × 5 = 45. Answer: 45π cm³
Cones, Cylinders & Spheres in New York
In the New York State Learning Standards, this is unit 16 of 19 in 8th grade Math, after Functions and before Slope & Rate of Change.
Gradelings describes a child's practice on this unit as Beginning, Approaching, Meeting or Exceeding (Four practice steps). That reflects practice, not a report-card mark: the teacher decides the mark.
Sample questions
A taste of this unit. In the app, questions change every time and get easier or harder to match your child.
Question 1
A cone and a cylinder have the same base and height. The cylinder holds 21 cm³. How much does the cone hold?
- 18 cm³
- 10.5 cm³
- 63 cm³
- 7 cm³
7 cm³
Hint: A cone holds one third of the matching cylinder.
Question 2
A cone has radius 6 in and height 12 in. What is its volume, in terms of π?
- 180π in³
- 432π in³
- 48π in³
- 144π in³
144π in³
Hint: V = ⅓πr²h = ⅓ × π × 6² × 12.
Question 3
A ball has radius 3 cm. What is its volume, in terms of π?
- 72π cm³
- 36π cm³
- 27π cm³
36π cm³
Hint: V = (4/3)πr³ = (4/3) × π × 27.
Question 4
A cylinder has radius 5 cm and height 10 cm. What is its volume, in terms of π?
- 1000π cm³
- 50π cm³
- 250π cm³
- 100π cm³
250π cm³
Hint: V = πr²h = π × 5² × 10.
Question 5
A can has radius 4 cm and height 10 cm. Using 3.14 for π, what is its volume in cm³?
answer boxcm³
502.4 cm³
Hint: V = 3.14 × 4² × 10.
Question 6
A ball has radius 6 cm. What is its volume, in terms of π?
- 288π cm³
- 144π cm³
- 576π cm³
- 216π cm³
288π cm³
Hint: V = (4/3)πr³ = (4/3) × π × 216.