9th grade · Math · Unit 18 of 18
Factoring & Quadratics
Factor and solve x² equations
What your child practices
Factoring quadratic expressions (common factors, trinomials, difference of squares) and solving quadratic equations by factoring and square roots.
Alabama Course of Study content standard: AIP.5; AIP.9 · factoring quadratic expressions and solving quadratic equations
How we explain it
Children can open this short lesson before they practice.
- To factor x² + bx + c, find two numbers that multiply to c and add to b.
- If a product is 0, one of the factors is 0.
- x² = k has two answers: √k and −√k.
Example: Solve x² + 5x + 6 = 0. 2 × 3 = 6 and 2 + 3 = 5: (x + 2)(x + 3) = 0. x + 2 = 0 or x + 3 = 0. Answer: x = −2 or x = −3
Factoring & Quadratics in Alabama
In the Alabama Course of Study, this is unit 18 of 18 in 9th grade Math, after Solving Systems.
Gradelings describes a child's practice on this unit as Beginning, Approaching, Meeting or Exceeding (Four practice steps). That reflects practice, not a report-card mark: the teacher decides the mark.
Sample questions
A taste of this unit. In the app, questions change every time and get easier or harder to match your child.
Question 1
Solve (x + 4)(x − 6) = 0.
- x = −24
- x = 2
- x = −4 or x = 6
- x = −6 or x = 4
x = −4 or x = 6
Hint: A product is 0 only when one factor is 0. Set each bracket equal to 0.
Question 2
Factor 15x + 35 completely.
- 5x(3x + 7)
- 15(x + 7)
- 5(15x + 7)
- 5(3x + 7)
5(3x + 7)
Hint: Both terms share a factor of 5.
Question 3
Solve 2x² = 98.
- x = 49
- x = 7 or x = −7
- x = 49 or x = −49
- x = 7
x = 7 or x = −7
Hint: Divide by 2, then take the square root. Don't forget the negative root.
Question 4
Factor x² + 11x + 18.
- (x + 11)(x + 1)
- (x + 9)(x − 2)
- (x + 9)(x + 2)
- (x − 9)(x − 2)
(x + 9)(x + 2)
Hint: Find two numbers that multiply to 18 and add to 11.
Question 5
Factor x² − 81.
- (x − 9)(x − 9)
- (x − 9)(x + 9)
- (x − 81)(x + 1)
- (x + 9)(x + 9)
(x − 9)(x + 9)
Hint: x² − a² is a difference of squares: (x − a)(x + a).
Question 6
Solve (x − 3)(x + 9) = 0.
- x = −3 or x = 9
- x = −27
- x = −9 or x = 3
- x = −6
x = −9 or x = 3
Hint: A product is 0 only when one factor is 0. Set each bracket equal to 0.