8th grade · Math · Unit 15 of 17
Cones, Cylinders & Spheres
Volume of round solids
What your child practices
Using the volume formulas for cylinders, cones and spheres, in terms of π and with 3.14.
Maine Learning Results learning standard: 8.G.C.9 · using the formulas for the volumes of cones, cylinders and spheres
How we explain it
Children can open this short lesson before they practice.
- Cylinder: V = πr²h.
- Cone: V = ⅓πr²h, one third of the matching cylinder.
- Sphere: V = (4/3)πr³.
Example: A cylinder has radius 3 cm and height 5 cm. What is its volume, in terms of π? r² = 9. 9 × 5 = 45. Answer: 45π cm³
Cones, Cylinders & Spheres in Maine
In the Maine Learning Results, this is unit 15 of 17 in 8th grade Math, after Functions and before Slope & Rate of Change.
Gradelings describes a child's practice on this unit as Beginning, Approaching, Meeting or Exceeding (Four practice steps). That reflects practice, not a report-card mark: the teacher decides the mark.
Source: Maine Department of Education
Sample questions
A taste of this unit. In the app, questions change every time and get easier or harder to match your child.
Question 1
A cone and a cylinder have the same base and height. The cylinder holds 12 cm³. How much does the cone hold?
- 6 cm³
- 4 cm³
- 9 cm³
- 36 cm³
4 cm³
Hint: A cone holds one third of the matching cylinder.
Question 2
A cone has radius 1 in and height 9 in. What is its volume, in terms of π?
- 9π in³
- 3π in³
- 4π in³
- 6π in³
3π in³
Hint: V = ⅓πr²h = ⅓ × π × 1² × 9.
Question 3
A cylinder has radius 3 cm and height 6 cm. What is its volume, in terms of π?
- 54π cm³
- 36π cm³
- 216π cm³
- 18π cm³
54π cm³
Hint: V = πr²h = π × 3² × 6.
Question 4
A ball has radius 6 cm. What is its volume, in terms of π?
- 288π cm³
- 576π cm³
- 144π cm³
- 216π cm³
288π cm³
Hint: V = (4/3)πr³ = (4/3) × π × 216.
Question 5
A can has radius 2 cm and height 9 cm. Using 3.14 for π, what is its volume in cm³?
answer boxcm³
113.04 cm³
Hint: V = 3.14 × 2² × 9.
Question 6
A cylinder has radius 4 cm and height 8 cm. What is its volume, in terms of π?
- 64π cm³
- 512π cm³
- 128π cm³
- 32π cm³
128π cm³
Hint: V = πr²h = π × 4² × 8.