9th grade · Math · Unit 14 of 17
Factoring & Quadratics
Factor and solve x² equations
What your child practices
Factoring quadratic expressions (common factors, trinomials, difference of squares) and solving quadratic equations by factoring and square roots.
Arizona Academic Standards learning standard: A1.A-REI.B.4; A1.A-SSE.B.3; A1.A-SSE.A.2 · factoring quadratic expressions and solving quadratic equations by factoring and taking square roots
How we explain it
Children can open this short lesson before they practice.
- To factor x² + bx + c, find two numbers that multiply to c and add to b.
- If a product is 0, one of the factors is 0.
- x² = k has two answers: √k and −√k.
Example: Solve x² + 5x + 6 = 0. 2 × 3 = 6 and 2 + 3 = 5: (x + 2)(x + 3) = 0. x + 2 = 0 or x + 3 = 0. Answer: x = −2 or x = −3
Factoring & Quadratics in Arizona
In the Arizona Academic Standards, this is unit 14 of 17 in 9th grade Math, after Linear or Exponential? and before Rearranging Formulas.
Gradelings describes a child's practice on this unit as Beginning, Approaching, Meeting or Exceeding (Four practice steps). That reflects practice, not a report-card mark: the teacher decides the mark.
Source: Arizona Department of Education
Sample questions
A taste of this unit. In the app, questions change every time and get easier or harder to match your child.
Question 1
Factor x² + 2x − 8.
- (x + 2)(x + 1)
- (x − 2)(x + 4)
- (x + 2)(x − 4)
- (x − 2)(x − 4)
(x − 2)(x + 4)
Hint: Find two numbers that multiply to −8 and add to 2.
Question 2
Solve 2x² = 50.
- x = 5 or x = −5
- x = 5
- x = 25
- x = 25 or x = −25
x = 5 or x = −5
Hint: Divide by 2, then take the square root. Don't forget the negative root.
Question 3
Solve (x − 7)(x + 7) = 0.
- x = −49
- x = −7 or x = 7
- x = 0
x = −7 or x = 7
Hint: A product is 0 only when one factor is 0. Set each bracket equal to 0.
Question 4
Factor x² − 121.
- (x − 121)(x + 1)
- (x + 11)(x + 11)
- (x − 11)(x − 11)
- (x − 11)(x + 11)
(x − 11)(x + 11)
Hint: x² − a² is a difference of squares: (x − a)(x + a).
Question 5
Factor 24x − 12 completely.
- 6(24x − 2)
- 6(4x − 2)
- 24(x − 2)
- 6x(4x − 2)
6(4x − 2)
Hint: Both terms share a factor of 6.
Question 6
Factor 6x + 15 completely.
- 3(6x + 5)
- 3(2x + 5)
- 6(x + 5)
- 3x(2x + 5)
3(2x + 5)
Hint: Both terms share a factor of 3.