9th grade · Math · Unit 12 of 16
Factoring & Quadratics
Factor and solve x² equations
What your child practices
Factoring quadratic expressions (common factors, trinomials, difference of squares) and solving quadratic equations by factoring and square roots.
Texas Essential Knowledge and Skills (TEKS) teks student expectation: A.8(A); A.10(E); A.10(F) · factoring trinomials and differences of squares, and solving quadratic equations
How we explain it
Children can open this short lesson before they practice.
- To factor x² + bx + c, find two numbers that multiply to c and add to b.
- If a product is 0, one of the factors is 0.
- x² = k has two answers: √k and −√k.
Example: Solve x² + 5x + 6 = 0. 2 × 3 = 6 and 2 + 3 = 5: (x + 2)(x + 3) = 0. x + 2 = 0 or x + 3 = 0. Answer: x = −2 or x = −3
Factoring & Quadratics in Texas
In the Texas Essential Knowledge and Skills (TEKS), this is unit 12 of 16 in 9th grade Math, after Expressions and before Exponents & Powers.
Gradelings describes a child's practice on this unit as Beginning, Approaching, Meeting or Exceeding (Four practice steps). That reflects practice, not a report-card mark: the teacher decides the mark.
Source: Texas Education Agency (TEA)
Sample questions
A taste of this unit. In the app, questions change every time and get easier or harder to match your child.
Question 1
Factor 3x − 18 completely.
- 3(x − 6)
- 3x(x − 6)
- 3(3x − 6)
3(x − 6)
Hint: Both terms share a factor of 3.
Question 2
Factor x² − 4.
- (x − 2)(x + 2)
- (x − 2)(x − 2)
- (x − 4)(x + 1)
- (x + 2)(x + 2)
(x − 2)(x + 2)
Hint: x² − a² is a difference of squares: (x − a)(x + a).
Question 3
Solve (x − 7)(x + 6) = 0.
- x = 1
- x = −6 or x = 7
- x = −7 or x = 6
- x = −42
x = −6 or x = 7
Hint: A product is 0 only when one factor is 0. Set each bracket equal to 0.
Question 4
Solve 2x² = 162.
- x = 9 or x = −9
- x = 81 or x = −81
- x = 81
- x = 9
x = 9 or x = −9
Hint: Divide by 2, then take the square root. Don't forget the negative root.
Question 5
Factor x² + 4x + 3.
- (x + 4)(x + 1)
- (x + 1)(x + 3)
- (x + 1)(x − 3)
- (x − 1)(x − 3)
(x + 1)(x + 3)
Hint: Find two numbers that multiply to 3 and add to 4.
Question 6
Solve 3x² = 48.
- x = 16 or x = −16
- x = 24
- x = 4
- x = 4 or x = −4
x = 4 or x = −4
Hint: Divide by 3, then take the square root. Don't forget the negative root.